Introduction

Area of a Circle:

Any geometrical shape has its own area. This area is the region occupied the shape in a two-dimensional plane. Now we will learn about the area of the circle. So the area covered by one complete cycle of the radius of the circle on a two-dimensional plane is the area of that circle

Area of a circle is πr2, where π=22/7 or ≈3.14 (can be used interchangeably for problem-solving purposes) and r is the radius of the circle.
π is the ratio of the circumference of a circle to its diameter.

Area of a Circle Formula:

Let us take a circle with radius r.

Area of a circle

where radius r from the centre ‘o’ to the boundary of the circle. Then the area for this circle, A, is equal to the product of pi and square of the radius. It is given by; 

Area of a Circle, A = πr2 square units

Perimeter and Area of a Circle — A Review :

Circumference of the circle or perimeter of the circle is the measurement of the boundary across any two-dimensional circular shape including circle.  Whereas the area of circle, defines the region occupied by it.  If we open a circle and make a straight line out of it, then its length is the circumference. It is usually measured in unit cm or unit m..

Circumference of a Circle Formula :

The Circumference (or) perimeter of a circle = 2πR

where,

R is the radius of the circle

π is the mathematical constant with an approximate (up to two decimal points) value of 3.14

Again,

Pi (π) is a special mathematical constant, it is the ratio of circumference to diameter of any circle.

where C = π D

C is the circumference of the circle

D is the diameter of the circle

For example: 

If Radius Of The Circle Is 4cm Then Find Its Circumference.

Solution:

Given:

 Radius = 4cm

Circumference = 2πr

= 2 x 3.14 x 4

= 25.12 cm

Circumference of Circle:

The circumference is the distance around a circle or any curved geometrical shape. It is the one-dimensional linear measurement of the boundary across any two-dimensional circular surface. It follows the same principle behind finding the perimeter of any polygon which is why calculating the circumference of a circle which is also known as the perimeter of a circle.

A circle is defined as a shape with all the points are equidistant from a point at the centre. The circle depicted below has its centre lies at point A.

The value of pi is approximately 3.1415926535897… and we use a Greek letter π (pronounced as Pi) to describe this number. The value π is a non-terminating value.

 

Circumference of a Circle

 

Example 1 :

The cost of fencing a circular field at the rate of ` 24 per metre is` 5280. The field is to be ploughed at the rate of ` 0.50 per m2. Find the cost of ploughing the field (Take π =22/7 ).

Solution :

 

For Rs. 24 , the length of fencing =1m

For Rs. 5280, the length of fencing = https://images.topperlearning.com/topper/questions/206802_image139.gif https://images.topperlearning.com/topper/questions/206802_image048.gif 5280 = 220 metres.

Circumference of the field = 220 m

2pr =220

2x https://images.topperlearning.com/topper/questions/206802_image135.gif https://images.topperlearning.com/topper/questions/206802_image048.gifr =220 https://images.topperlearning.com/topper/questions/206802_image144.gif

Area of the field =  https://images.topperlearning.com/topper/questions/206802_0e03aee651ebc79d708627d9a16b6710.png r2 =  https://images.topperlearning.com/topper/questions/206802_0e03aee651ebc79d708627d9a16b6710.png (35)2 =1225https://images.topperlearning.com/topper/questions/206802_0e03aee651ebc79d708627d9a16b6710.png m2

Cost of ploughing = Rs. 0.50 per m2

Total cost of ploughing the field = Rs. 1225 https://images.topperlearning.com/topper/questions/206802_0e03aee651ebc79d708627d9a16b6710.png x 0.50

= Rs. https://images.topperlearning.com/topper/questions/206802_image146.gif

 

Areas of Sector and Segment of a Circle :

 Definition :

A segment of a circle can be defined as a region bounded by a chord and a corresponding arc lying between the chord’s endpoints. So, it can be said that a circular segment is a region of a circle which is created by breaking apart from the rest of the circle through a secant or a chord.

Types of Segments in a Circle :

 There are two classifications of segments in a circle namely the major segment and the minor segment. The segment having larger area is known as the major segment and the segment having a smaller area is known as minor segment.

 

Types of segment in a circle

 

Area of a Segment of a Circle Formula :

The formula to find segment area can be either in terms of radians or in terms of degree.

 

Area of a Segment of a Circle Formula

 

Example 2 :

 Find the area of the sector of a circle with radius 4 cm and of angle 30°. Also, find the area of the corresponding major sector (Use π = 3.14).

Solution :

Area Of Sector =Θ / 360Πr2

=Θ360πr2
=30/360
3.1442
=1 / 2–√
3.1416

=12.56 / 3

=4.186cm2
now, area of major sector =π
r24.186cm2
=3.14
164.186
=50.244.186
=46.054cm2

Area of combinations of plane figures :

A collection of points that are on a plane is known as a plane figure.

Calculate the area of the figure, which has a non-standard form is involving basic geometric figures such as circles, squares, triangles, rectangles etc.

https://d34h5de3fkci09.cloudfront.net/1674/data/5aa7094b-b2cf-11e9-b046-02d8bc535ac2/5aa7094b-b2cf-11e9-b046-02d8bc535ac2.app

Area of the figure = Area of the rectangle + 2 x Area of semi circles.

https://d34h5de3fkci09.cloudfront.net/1674/data/5aa72410-b2cf-11e9-b046-02d8bc535ac2/5aa72410-b2cf-11e9-b046-02d8bc535ac2.app

 Area of the  required region = 34
( πr1– πr22).

https://d34h5de3fkci09.cloudfront.net/1674/data/5aa70178-b2cf-11e9-b046-02d8bc535ac2/5aa70178-b2cf-11e9-b046-02d8bc535ac2.app

Area of the  required region = πr2 – a2 .

 

Example 5 :

 Find the area of the shaded region where ABCD is a square of side 14cm . ( four equal circle inside the square)

 

download.png

 

Area of Square ABCD

14 * 14 cm2

= 196 cm2

Diameter of each Circle

14 / 2 cm

= 7 cm

Radius of each Circle

= 7 /2 cm

Area of one Circle

= πr2

= 22 / 7 * 7 / 2 * 7 / 2

= 154 / 4

= 77 / 2 cm2

Area of Four Circle

4* 77 / 2cm2

= 154 cm2

Area of Shaded Region

Area of Shaded Region = Area of Square ABCD - Area of four Circles

= ( 196 - 154 ) cm2

= 42 cm2

Example :6

 Find the area of the shaded design in Fig. 12.17, where ABCD is a square of side 10 cm and semicircles are drawn with each side of the square as diameter. (Use π = 3.14)

 

d1.jpg

Let Unshaded regions be 1, 2, 3 and 4

                                                Area of 1 + Area of 3= Area of ABCD – Areas of two semicircles of each of radius 5 cm 

Area of 1 and 3 = ( 10 * 10 - 2 * 1/2 * 3.14 * 5 *5)  [Area of semi circle =  1/2  pie r²]

                          = (100 - 3.14 * 25)

                          = (100 - 78.5)

                          =21.5 cm²

So,

Even the Area of 2 and 4 is equal to 21.5cm²

So,

Area of shaded region = Area of ABCD - Area 0f( 1+2+3+4)

                                                                          = 100 - (21.5 + 21.5)

                                                                       = 100 - 43

Area of shaded region = 57cm²