Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages.

Matching exercise

Match the items on the right to the items on the left.

STEP 1

STEP 2

STEP 3

STEP 4

Let the present age of father be ‘a’ and present age of son be b.

Given, ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then.

⇒ a – 10 = 12(b – 10) ⇒ a = 12b + 110 ------ (1)

Also, a + 10 = 2(b + 10)

⇒ a = 2b + 10 ------- (2)

Equating eq1 and eq2.

⇒ 12b + 110 = 2b + 10

⇒ b = 10

Thus, a = 30