The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages.

Matching exercise

Match the items on the right to the items on the left.

STEP 1

STEP 2

STEP 3

STEP 4

Let the father’s age be ‘a’ and son’s age be ‘b’

Given, present age of a father is three years more than three times the age of the son.

⇒ a = 3b + 3 ---------- (1)

Also, three years hence father’s age will be 10 years more than twice the age of the son.

⇒ a + 3 = 2(b + 3) + 10

⇒ a = 2b + 13 --------- (2)

Equating (1) and (2), we get

3b + 3 = 2b + 13

⇒ b = 10 years

Father’s age (a) = 3 × 10 + 3 = 33