Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

Matching exercise

Match the items on the right to the items on the left.

STEP 1

STEP 2

STEP 3

STEP 4

STEP 5

Let the present age of father be ‘a’ and present sum of age of both sons be b.

Given, Father’s age is three times the sum of ages of his two children.

⇒ a = 3b

After 5 years his age will be twice the sum of ages of two children.
So age of father will be a + 5 and as there are two sons, age of both sons combined after 5 years will be b + 10.
⇒ a + 5 = 2(b + 10)

Put the value of a in above equation,
⇒ 3b + 5 = 2b + 20

⇒ 3b - 2b = 20 - 15
⇒ b = 15

Thus, a = 3b = 3 (15) = 45

Hence father's present age is 45 years.