Consider f:R+→[-5,∞] given by f(x)=9x2+6x-5. Show that f is invertible with f-1(x)=x+6-13

Consider f: $R^{+} \to [- 5, \infty]$ given by f(x)= $9 x^{2} + 6 x - 5$ . Show that f is invertible with $f^{- 1} (x) = \frac{\sqrt{x + 6} - 1}{3}$

Matching exercise

Match the items on the right to the items on the left.

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