For any a, b, x, y > 0, prove that 23 tan-1 3ab2-a3b3-3a2b + 23 tan-1 3xy2-x3y3-3x2y = </m

For any a, b, x, y > 0, prove that $\frac{2}{3} \tan^{- 1} (\frac{3 a b^{2} - a^{3}}{b^{3} - 3 a^{2} b}) + \frac{2}{3} \tan^{- 1} (\frac{3 x y^{2} - x^{3}}{y^{3} - 3 x^{2} y}) = </mMatching exerciseMatch the items on the right to the items on the left.CheckOKStep 1Step 2Step 3Step 4Step 5Step 6Step 7Step 8Step 9Step 10Step 11$