ABC is triangle in which AB = AC and P is a point on AC. Through C a line drawn to intersect BP produced at Q such that angle ABQ = ACQ. Prove that ∠AQC= 90°+12∠BAC

ABC is triangle in which AB = AC and P is a point on AC. Through C a line drawn to intersect BP produced at Q such that angle ABQ = ACQ. Prove that $∠ A Q C = 90 ° + \frac{1}{2} ∠ B A C$

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