Given that f(x)=x-1 x≥14 x<1 (i) f(0)(ii) f(3)(iii) f(a + 1) in terms of a.(Given that a > =0)

Given that $f (x) = \{\begin{cases} \sqrt{x - 1} x \geq 1 \\ 4 x < 1 \end{cases}$ (i) f(0)
(ii) f(3)
(iii) f(a + 1) in terms of a.(Given that a > =0)

Matching exercise

Match the items on the right to the items on the left.

Step - 1

Step - 2

Step - 3