The perpendicular PS on the base QR of a ∆PQR intersects QR at S, such that QS=3 SR. Prove that 2PQ2=2PR2+QR2

The perpendicular PS on the base QR of a $∆ P Q R$ intersects QR at S, such that QS=3 SR. Prove that $2 P Q^{2} = 2 P R^{2} + Q R^{2}$

Matching exercise

Match the items on the right to the items on the left.

Step 1

Step 2

Step 3

Step 4

Step 5

screenshot4.3_7_2.png

screenshot4.3_7_4.png

screenshot4.3_7_1.png

screenshot4.3_7_5.png

screenshot4.3_7_3.png