Mensuration

Gap-fill exercise

  
Fill in all the gaps, then press "Check" to check your answers. Use the "Hint" button to get a free letter if an answer is giving you trouble. You can also click on the "[?]" button to get a clue. Note that you will lose points if you ask for hints or clues!
Write true or false: (Q1 - Q10)
1. Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is 16πr2.
2. A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape so formed is 4πrh + 4πr2.
3. A solid cone of radius r and height h is placed over a solid cylinder having same base radius and height as that of a cone. The total surface area of the combined solid is πr r2 + h2 + 3r + 2h.
4. A solid ball is exactly fitted inside the cubical box of side a. The volume of the ball is 43πa3.
5. f2q5.PNG
The capacity of a cylindrical vessel with a hemispherical portion raised upward, at the bottom as shown in figure is πr233h - 2r.
6. he volume of the frustrum of cone is 13πr2 + R2 - rRh, where h is the vertical height of the frustrum and r, R are the radii of the ends.
7. The curved surface area of a frustrum of a cone is πlr1 + r2, where l = h2 + r12 + r22, r1 and r2 are the radii of the two ends of frustrum and h is vertical height.
8. An open metallic bucket is in the shape of a frustrum of a cone, mounted on a hollow cylindrical base made of the same metallic sheet. The surface area of the metallic sheet used is equal to the curved surface area of frustrum of a cone + area of circular base + curved surface area of cylinder.
9. Let R and r be the external and internal radii of a hollow cylinder of height h. Then its total surface area is 2πR + r R + h - r.
10. A bucket is an example of a frustums of cone.