Prove that tan θ + sec θ - 1tan θ - sec θ + 1 =1 + sinθ cos θ.

Prove that $\frac{\tan θ + s e c θ - 1}{\tan θ - s e c θ + 1} = \frac{1 + \sin θ}{\cos θ}$ .

Matching exercise

Match the items on the right to the items on the left.

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STEP 5