If sin θ + cos θ=m, show that sin6θ + cos6θ=4-3(m2-1)24, where m2≤2 .

If $\sin θ + \cos θ = m$ , show that $\sin^{6} θ + \cos^{6} θ = \frac{4 - 3 (m^{2} - 1)^{2}}{4}, w h e r e m^{2} \leq 2$ .

Matching exercise

Match the items on the right to the items on the left.

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