If θ + φ = α and tan θ =ktan φ , then prove that sin (θ - α) = k

If $θ + φ = α a n d \tan θ = k \tan φ$ , then prove that $\sin (θ - α) = \frac{k - 1}{k + 1} \sin α$ .

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If θ + φ = α and tan θ =ktan φ , then prove that sin (θ - α) = k - 1k + 1sin α .

If $θ + φ = α a n d \tan θ = k \tan φ$ , then prove that $\sin (θ - α) = \frac{k - 1}{k + 1} \sin α$ .