Prove that sin 8x cos x - sin 6x cos3xcos 2x cos x -sin 3x sin 4x= tan 2x .

Prove that $\frac{\sin 8 x \cos x - \sin 6 x \cos 3 x}{\cos 2 x \cos x - \sin 3 x \sin 4 x} = \tan 2 x$ .

Matching exercise

Match the items on the right to the items on the left.

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STEP 4