Prove that cot (A + 15°) - tan (A -15°) = 4 cos 2A1 + 2 sin 2A .

Prove that $c o t (A + 15 °) - \tan (A - 15 °) = \frac{4 \cos 2 A}{1 + 2 \sin 2 A}$ .

Matching exercise

Match the items on the right to the items on the left.

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