If ω≠1 is a cube root of unity, show that (1+ω)(1+ω2)(1+ω4)(1+ω8)...(1+ω211)=1

If ω≠1 is a cube root of unity, show that $(1 + ω) (1 + ω^{2}) (1 + ω^{4}) (1 + ω^{8}) . . . (1 + ω^{2^{11}}) = 1$

Matching exercise

Match the items on the right to the items on the left.

Step 1

Step 2

Step 3

Step 4

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