Q.6 Cross section of a Nuclear cooling tower is in the shape of a hyperbola with equation x2302-y2442=1. The tower is 150m tall and the distance from the top of the tower to the centre of the hyperbola is half the distance from the base of the tower to the centre of the hyperbola. Find the diameter of the top and base of the tower.

Q.6 Cross section of a Nuclear cooling tower is in the shape of a hyperbola with equation $\frac{x^{2}}{30^{2}} - \frac{y^{2}}{44^{2}} = 1$ . The tower is 150m tall and the distance from the top of the tower to the centre of the hyperbola is half the distance from the base of the tower to the centre of the hyperbola. Find the diameter of the top and base of the tower.

$f (x) = \{\begin{matrix} \frac{\sin (a + 1) x + \sin x}{x}, f o r x < 0 \\ x, f o r x = 0 \\ \frac{\sqrt{x + b x^{2}} - \sqrt{x}}{b x^{\frac{3}{2}}}, f o r x > 0 \end{matrix}$

Put the parts in order to form a sentence. When you think your answer is correct, click on "Check" to check your answer. If you get stuck, click on "Hint" to find out the next correct part.

f(x)=sina+1x+sinxx, for x<0x, for x=0x+bx2-xbx32, for x>0

$f (x) = \{\begin{matrix} \frac{\sin (a + 1) x + \sin x}{x}, f o r x < 0 \\ x, f o r x = 0 \\ \frac{\sqrt{x + b x^{2}} - \sqrt{x}}{b x^{\frac{3}{2}}}, f o r x > 0 \end{matrix}$