Find the mean for the following distribution using step Deviation Method.
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Gap-fill exercise

  
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Let Assumed mean A = 28. Class width C = 8


Class Interval Mid value (x)Frequency (f)d = (x-A)/cfd
0-8410-3
8- 161220-2-40
16-242014-1-14
24-3228160
32-403618118
40 - 484422244
  Σf =  Σfd =


Mean = x¯=A+ΣfdΣf×c = 28+-22100×8 = 28-1.76= =